C program to find the number of nodes present in the entered Linked List

PROGRAM:
#include<stdio.h>
struct node
{
int data;
struct node *next;
} *head,*temp,*temp1;
void create();
void find();
void print();
void main()
{
create();
printf("\nElements in the entered list:\n");
print();
find();

}
void create()
{
int num;
printf("\nEnter element or enter -1 to exit\n");
head=(struct node*)malloc(sizeof(struct node));
scanf("%d",&num);
if(num==-1)
{
head=NULL;
}
else
{
head->data=num;
head->next=NULL;
}
while(head!=NULL)
{
printf("\nEnter element or enter -1 to exit\n");
scanf("%d",&num);
if(num==-1)
{break;}
else
{
temp=head;
while(temp->next!=NULL)
{
temp=temp->next;
}
temp1=(struct node*)malloc(sizeof(struct node));
temp1->data=num;
temp1->next=NULL;
temp->next=temp1;
}
}
}
/*Find function finds the number of nodes present in the entered linked list*/
void find()
{
int count;
for(temp=head,count=0;temp!=NULL;temp=temp->next,count++);
printf("\n\nEntered Linked list has %d nodes.",count);
}
void print()
{
struct node *head1=head;
while(head1!=NULL)
{
printf("%d\t",head1->data);
head1=head1->next;
}
}

OUTPUT: